Most probable rupture force under a linear ramp
= Most probable rupture force under a linear ramp
{title2=$F_*=\max\{0,F_0\log[f/(k_0F_0)]\}$}
Differentiate the logarithm of the rupture-force <probability density> $k(F)p(F)/f$. Its interior stationary point satisfies $e^{F/F_0}=f/(k_0F_0)$. The physical domain is $F\geq0$, giving the displayed <mode>. This differs from the <median rupture force under a linear ramp>; replacing one by the other shifts a fitted intercept and can bias the inferred zero-force rate.