Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 134 2 iv a Solution Created 2026-10-03 Updated 2026-10-05
By Kodaira's lemma for the big divisor , choose an integer , an ample Cartier divisor , and an effective divisor withIf an integral curve is not a component of , nonnegative intersections of distinct curves giveThus every curve with is one of the finitely many components of . In particular,This is the surface case of negative curves of a big real divisor lie in finitely many divisors. The proof does not assert that every negative curve on belongs to this finite set; it concerns curves negative against this particular big canonical class.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 134 3 ii Solution Created 2026-10-03 Updated 2026-10-05
First work on an integral component. Write the big real divisor as with ample real divisor and effective real Cartier, using Kodaira's lemma. Let be the finitely many integral components of its support. For an integral projective curve not contained in this support, restriction of each effective Cartier summand to is effective, soThereforeThis proves negative curves of a big real divisor lie in finitely many divisors.
Now let be the given ample divisor. Openness of the ample cone gives a such that is ample for . For each of the finitely many , the assumption that is ample similarly gives a such that is ample for . Choose a single positive smaller than all these bounds.
If is contained in some , its intersection with is positive by that restriction. OtherwiseIn particular is nef:Only the finitely many exceptional support components are needed for the restriction test; no uniform bound over all subvarieties was assumed.
For a reducible projective scheme, use componentwise bigness on a projective scheme and repeat this argument on each reduced irreducible component. Collect their exceptional supports and take the minimum of all the finitely many positive bounds. Codimension one here is measured in the relevant irreducible component. Every integral curve lies in a component, so the same conclusion holds on . Nilpotent structure does not affect these curve intersection numbers.