Nondifferentiable factor with a differentiable nondegenerate product
= Nondifferentiable factor with a differentiable nondegenerate product
At zero, $f(x)=x$ and $g(x)=1+|x|$ give a differentiable product
$$
f(x)g(x)=x+x|x|
$$
with derivative one, although $g$ is not differentiable.