Normal location-scale score
= Normal location-scale score
For $N(\mu,v)$, the one-observation score is $((x-\mu)/v,-1/(2v)+(x-\mu)^2/(2v^2))$ and the information matrix is $\operatorname{diag}(v^{-1},(2v^2)^{-1})$.
= Normal location-scale score
For $N(\mu,v)$, the one-observation score is $((x-\mu)/v,-1/(2v)+(x-\mu)^2/(2v^2))$ and the information matrix is $\operatorname{diag}(v^{-1},(2v^2)^{-1})$.