One-dimensional stationary-phase formula
= One-dimensional stationary-phase formula
If $\psi'(k_0)=0$, $\psi''(k_0)\ne0$, and $A$ is smooth near $k_0$, then
$$
\int A(k)e^{it\psi(k)}\,dk
\sim A(k_0)e^{it\psi(k_0)+i\pi\operatorname{sgn}(\psi''(k_0))/4}
\sqrt{\frac{2\pi}{t|\psi''(k_0)|}}.
$$
Contributions from distinct stationary points add.