Operator trace
= Operator trace
{title2=$\operatorname{tr}T$}
For a trace-class operator, the series $\operatorname{tr}T=\sum_n\langle Te_n,e_n\rangle$ converges absolutely and is independent of the orthonormal basis. It satisfies $|\operatorname{tr}T|\leq\|T\|_1$.
The <trace-class operator> condition makes this <operator trace> well-defined; the class of eligible operators and the trace functional are distinct concepts.