Away from a bifurcation set, the normal to a Killing horizon is its nonzero Killing vector field . Any affine tangent to the same generators has the form . In the optical tensor, derivatives of contribute a factor of and disappear under the screen-space projector. Consequently
by the Killing equation. The trace and trace-free symmetric part are therefore zero: and .
For the antisymmetric part, locally the horizon normal is proportional to a gradient. The restriction of its dual one-form to every tangent direction on the horizon is zero. Taking its exterior derivative and evaluating on two screen tangents therefore gives zero as well; equivalently this is the hypersurface-orthogonality consequence of the Frobenius theorem. Since both screen indices are tangential, . Thus the optical scalars on a Killing horizon satisfy
No affine normalization of the Killing vector field itself was assumed. At a regular bifurcation surface, vanishes but the smooth null generators do not; the conclusions for their optical quantities follow by continuity along each horizon branch.
Let generate the Killing horizon and let be an affinely parametrized generator wherever . Choose an auxiliary null vector with and the screen-space projector . The optical tensor is the screen projection .
Since the projector annihilates , the symmetric part is
by the Killing equation. Its trace is the null expansion and its trace-free symmetric part is the null shear, so both vanish. Also is normal to the null hypersurface. Frobenius theorem gives , which implies : the null twist vanishes. These arguments use derivatives tangent to the horizon and hence apply to any smooth null geodesic congruence containing its generators, independently of its extension off the horizon. At a regular bifurcation surface, use the smooth affine generator and continuity. Thus
This is the vanishing of the optical scalars on a Killing horizon.