Orthogonal eigenvectors of a compact operator
= Orthogonal eigenvectors of a compact operator
If $Tx_j=\lambda_jx_j$ for an infinite orthonormal sequence $(x_j)$ and a compact operator $T$ on a <Hilbert space>, then $\lambda_j\to0$. Otherwise a subsequence of the vectors $Tx_j$ stays pairwise separated, contradicting compactness.