Parity basis of a one-dimensional S-matrix
= Parity basis of a one-dimensional S-matrix
{c}
For a <parity>[parity-symmetric] one-dimensional potential, the even and odd parity states diagonalize the <One-dimensional S-matrix>:
$$
S_{+-}=S_{-+}=0,
\qquad
S=\operatorname{diag}(S_{++},S_{--}).
$$
For a real potential, <unitary operator>[unitarity] further gives $|S_{++}|=|S_{--}|=1$ at real positive energy.