Solution
= Solution
Suppose a single <basis> gives the <diagonal matrices> $D_S,D_T$. Entrywise multiplication gives $D_SD_T=D_TD_S$. If $P$ is the <change-of-basis matrix>, then
$$
ST=P D_SD_TP^{-1}=P D_TD_SP^{-1}=TS.
$$
Thus \b[<simultaneous diagonalization> implies commutation].