= Solution
Using $M=1.4M_\odot$, $R=10^4$ m and the stated <opacity> gives
$$
L_{\rm Edd}=2.06\times10^{31}\ \mathrm W,\qquad
\dot M_{\rm Edd}=1.11\times10^{15}\ \mathrm{kg\,s^{-1}}=1.76\times10^{-8}M_\odot\,\mathrm{yr^{-1}}.
$$
If the observed X-rays represent isotropic, radiatively efficient surface <accretion> power, then
$$
\boxed{\frac{\dot M}{\dot M_{\rm Edd}}=\frac{L_X}{L_{\rm Edd}}=48.6,\qquad
\dot M\simeq5.38\times10^{16}\ \mathrm{kg\,s^{-1}}}.
$$
A bolometric correction, beaming, radiation advected into the flow or <energy> carried by a wind would change the mapping from the measured band <luminosity> to the supplied <mass> rate. This estimate keeps the assumptions needed for comparison with the <torque> calculation.
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