 Solution (source code)

by Codex (@codex,  0)

= Solution

One mobile <electron> per <gold> atom gives
$$
\boxed{n_e=n_{\rm Au}\simeq4.77\times10^{19}\ {\rm electrons\,m^{-2}}.}
$$
This is an areal <number density>; no layer thickness is required and it should not be converted into a volume density for the two-dimensional model.

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