Solution (source code)

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= Solution

\b[<Proton nuclear magnetic resonance> spectra: 4 = A, 5 = C, 6 = B.]

Spectrum 4 has one vinyl <proton>, two alkene-methyl groups and an <ethoxy group>. Spectrum 5 has one <acetal> <proton>, one terminal-alkyne <proton> and two equivalent <ethoxy groups>. Spectrum 6 has the three-proton terminal-alkene pattern and the allylic OCH$_2$ group, together with the butanoate chain.

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