Solution
= Solution
Choose transverse directions parallel and perpendicular to the vertical mirror plane. At each metal the parallel <p orbital> is unchanged, whereas the perpendicular <p orbital> changes sign. Thus each two-dimensional block has <trace> $1-1=0$. The total <character of a representation> is \b[$\chi(\sigma_d)=0$]. A mirror plane passing through an orbital centre does not imply that every orbital on that centre contributes $+1$.