Reflection $x\mapsto a-x$ preserves the walls and kinetic operator but sends $\lambda(x-a/2)$ to $-\lambda(x-a/2)$. The Hamiltonians at $\lambda$ and $-\lambda$ are unitarily equivalent, so each analytic nondegenerate energy branch obeys $E_n(\lambda)=E_n(-\lambda)$. Its Taylor expansion contains only even powers: all odd-order energy coefficients vanish, not merely the first-order expectation.


Solution

Past exam of the chemistry course of the year 3 of the natural sciences course of the University of Cambridge / 2022 / Paper 4 / 59 / b / iii / Solution

 Solution (source code)