\b[Yes: choose $Y=4/X$.] The equilibrium <expected payoffs> are opposite because this is a <zero-sum game>. They are equal exactly when both are zero. Part (b)'s value vanishes exactly when $XY=4$, and $4/X>0$ for every allowed $X>0$. This establishes both existence and the unique suitable positive choice of $Y$.

Solution

Past exam of the computer science course of the University of Oxford / 2018 / Computational game theory / 1 / c / Solution

 Solution (source code)