Solution
= Solution
At the left endpoint, both computed <outer expansion> terms vanish, so $y_{\rm out}(0)=0$ agrees with the boundary data. At the right endpoint,
$$
y_{\rm out}(1)=1-\epsilon+O(\epsilon^2),
$$
which differs by order one from the required zero value. Hence \b[the boundary layer is at $x=1$]. The left boundary requires no order-one layer for this outer branch.