= Solution
Use the <constitutive relations> $\mathbf D=\epsilon\mathbf E$ and $\mathbf H=\mathbf B/\mu$, where $\mathbf D$ is the <electric displacement field>, $\mathbf H$ the <magnetic field strength>, $\epsilon$ the <permittivity>, and $\mu$ the <magnetic permeability>. Let $\rho_f$ be the <charge density> of <free charge> and $\mathbf J_f$ its <current density>. In this homogeneous medium, <Gauss's law> and the <magnetostatic Ampère law> are, respectively,
$$
\boxed{\nabla\cdot\mathbf D=\rho_f,\qquad
\oint_{\partial W}\mathbf D\cdot\mathbf n\,dS=Q_f(W)=\int_W\rho_f\,d^3r,}
$$
$$
\boxed{\nabla\times\mathbf H=\mathbf J_f,\qquad
\oint_{\partial S}\mathbf H\cdot d\boldsymbol\ell=I_f(S)=\int_S\mathbf J_f\cdot\mathbf n\,dS.}
$$
Here $W$ is a volume with closed boundary $\partial W$, and $S$ is an oriented spanning surface whose boundary orientation follows the right-hand rule. Thus the <electric field> form is $\nabla\cdot\mathbf E=\rho_f/\epsilon$ and $\oint_{\partial W}\mathbf E\cdot\mathbf n\,dS=Q_f/\epsilon$; the <magnetic field> form is $\nabla\times\mathbf B=\mu\mathbf J_f$ and $\oint_{\partial S}\mathbf B\cdot d\boldsymbol\ell=\mu I_f$.
The remaining static <Maxwell equations> are
$$
\nabla\cdot\mathbf B=0,\qquad\oint_{\partial W}\mathbf B\cdot\mathbf n\,dS=0,
\qquad
\nabla\times\mathbf E=0,\qquad\oint_{\partial S}\mathbf E\cdot d\boldsymbol\ell=0.
$$
These express <Gauss's law for magnetism> and the static limit of <Faraday's law>. The volume and circulation forms follow from the <divergence theorem> and <Stokes theorem>. The <electric charge> and <electric current> on the right of the macroscopic laws are free sources; material <electric polarization> and <magnetization> are already included in $\mathbf D$ and $\mathbf H$.
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