{c}

\b[No.] A motionless isolated <point mass> produces a static <gravitational field>. All its <mass multipole moments> are time independent, so there is no outgoing <gravitational radiation>. In the <quadrupole formula>, $h_{ij}^{\rm TT}\propto d^2Q_{ij}^{\rm TT}/dt^2=0$.

Solution

Past exam of the general relativity course of the University of Oxford / 2021 / 2 / a / i / Solution

 Solution (source code)