Solution
= Solution
\b[Yes.] The usual order on the <rational numbers> is strict and linear. Between $a<b$ lies the rational midpoint $(a+b)/2$, and $a-1,a+1$ witness absence of endpoints. Thus it is a <dense linear order without endpoints>.
= Solution
\b[Yes.] The usual order on the <rational numbers> is strict and linear. Between $a<b$ lies the rational midpoint $(a+b)/2$, and $a-1,a+1$ witness absence of endpoints. Thus it is a <dense linear order without endpoints>.