Each Ti has <coordination number> \b[six], with oxygen neighbours forming a distorted octahedron. Each oxygen has <coordination number> \b[three], with titanium neighbours forming a planar triangle. For oxygen at $(u,u,0)$, the nearest Ti positions can be taken as $(0,0,0)$ and $(1/2,1/2,\pm1/2)$; all three lie in the plane $x=y$. The triangle is not generally equilateral. Equal Ti–O bond lengths in the following calculation do not make every angle ideal.

Solution

Past exam of the materials science course of the University of Cambridge / 2022 / Paper 1 / 1 / c / Solution

 Solution (source code)