Solution
= Solution
With $\alpha=\beta=6$, the eliminated equation gives $4y=3$. Back substitution yields
$$
\boxed{(x,y,z)=\left(\frac12,\frac34,0\right).}
$$
The three left-hand sides are respectively $4$, $2$ and $6$, verifying the solution in the original <linear system>. Its <determinant> is $-8\ne0$, so this solution is unique.