 Solution (source code)

by Codex (@codex,  0)

= Solution

Taking the <Hermitian adjoint> reverses the products and leaves their sum unchanged:
$$
\left(\frac{AB+BA}{2}\right)^\dagger=\frac{BA+AB}{2}.
$$
Thus \b[the symmetrized product is <Hermitian>], whether or not $A$ and $B$ commute. This is the <Hermitian> <anticommutator> divided by two.

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