Solution
= Solution
By <Vieta's formulas>, the sum of all five <polynomial roots>, counted with <multiplicity of a root>, is minus the coefficient of $z^4$ divided by the leading coefficient. Hence
$$
\boxed{\sum_{j=1}^5z_j=5.}
$$
= Solution
By <Vieta's formulas>, the sum of all five <polynomial roots>, counted with <multiplicity of a root>, is minus the coefficient of $z^4$ divided by the leading coefficient. Hence
$$
\boxed{\sum_{j=1}^5z_j=5.}
$$