Solution
= Solution
By the <product rule> and <chain rule>,
$$
f'(x)=e^{x^2}(1+2x^2)>0\qquad(x\in\mathbb R).
$$
Thus there are $\boxed{0}$ <stationary points>; the function is strictly increasing everywhere.
= Solution
By the <product rule> and <chain rule>,
$$
f'(x)=e^{x^2}(1+2x^2)>0\qquad(x\in\mathbb R).
$$
Thus there are $\boxed{0}$ <stationary points>; the function is strictly increasing everywhere.