Solution
= Solution
\b[True.] In a <connected sum of knots>, a <bracket smoothing state> from each summand contributes a state of the joined diagram. Joining the two distinguished state <circles> reduces their total count by one, so the factors $\delta^{s-1}$ multiply. The smoothing weights also multiply and the <writhe of a link diagram> adds. Thus the <Jones polynomial of a connected sum> is
$$
\boxed{V_{K_1\#K_2}(t)=V_{K_1}(t)V_{K_2}(t).}
$$