Solution
= Solution
For $n\ge2$, $0<n^{-2}\le[n(n-1)]^{-1}=1/(n-1)-1/n$. The upper bound has telescoping partial sums, bounded by one. The positive partial sums of the original <series> are consequently bounded by two and increasing, so they converge as a <monotone bounded sequence>. \b[The series converges absolutely.] This also supplies the $p=2$ case of a <p-series> without requiring its exact sum.