Solution
= Solution
Let $[v]_\times$ denote the <cross product> matrix, with $[v]_\times x=v\times x$. Then
$$
\boxed{A=uu^T+[v]_\times,\qquad A_{ij}=u_iu_j-\epsilon_{ijk}v_k.}
$$
The two <eigenvalue> calculations use an <orthonormal basis> adapted to $u,v$.