Solution
= Solution
\b[True.] If $Av=\lambda v$ with $v\ne0$ and $A=A^*$, then
$$
\lambda v^*v=v^*Av=(v^*Av)^*=\bar\lambda v^*v.
$$
Since $v^*v>0$, $\lambda=\bar\lambda$. Thus every <eigenvalue> of a <Hermitian matrix> is real.
= Solution
\b[True.] If $Av=\lambda v$ with $v\ne0$ and $A=A^*$, then
$$
\lambda v^*v=v^*Av=(v^*Av)^*=\bar\lambda v^*v.
$$
Since $v^*v>0$, $\lambda=\bar\lambda$. Thus every <eigenvalue> of a <Hermitian matrix> is real.