Solution
= Solution
In the <induced character> formula above, there are no $x\in G$ with $x^{-1}gx\in H$ when the <conjugacy class> of $g$ misses $H$. The sum is empty, so \b[$(\operatorname{Ind}_H^G\psi)(g)=0$.]
= Solution
In the <induced character> formula above, there are no $x\in G$ with $x^{-1}gx\in H$ when the <conjugacy class> of $g$ misses $H$. The sum is empty, so \b[$(\operatorname{Ind}_H^G\psi)(g)=0$.]