Solution
= Solution
\b[The intersection is always an <equivalence relation>.] Both component relations contain $(x,x)$, so $V$ is a <reflexive relation>. If $xVy$, both relations relate $x$ to $y$, and symmetry in each gives $yVx$. If $xVy$ and $yVz$, <transitivity> in each component gives both $xRz$ and $xSz$, hence $xVz$. This is the <intersection of equivalence relations>; the same argument works for any family of such relations.