= Solution
There are 23 independent vial responses. The intercept-only fit has 22 residual <statistical degrees of freedom> and deviance 33.631. Adding two day indicators removes two <statistical degrees of freedom> and reduces the <residual deviance> by $33.631-33.358=0.273$. Adding the two species indicators then reduces it by $33.358-14.646=18.712$. Thus the six replacements, in their printed order, are \b[$22,\ 33.631,\ 2,\ 0.273,\ 18.712,\ 14.646$].
The <residual deviance> <statistical degrees of freedom> are $23-1=22$, $23-3=20$, and $23-5=18$. These sequential analysis-of-deviance rows compare nested <generalized linear models> in the displayed order. In an unbalanced design, the first day row does not test day after controlling for species.
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