Solution
= Solution
Take $G=C_2\times C_2$ and $N=C_2\times\{1\}$. Both are nontrivial, and $N$ is normal because $G$ is abelian. The second-coordinate projection identifies the <quotient group> $G/N$ with $C_2$. Swapping the two coordinates identifies $(G/N)\times N$ with $G$, so
$$
\boxed{G=C_2\times C_2,\quad N=C_2\times\{1\},\quad (G/N)\times N\cong G.}
$$
This is a <direct product of groups> with its first factor as the specified <normal subgroup>.