= Solution
The agreement is in the \b[energy levels, not in electron trajectories]. The <Bohr model> assumes a particle on a circular orbit, with <orbital angular momentum> quantized as $N\hbar$. The <Coulomb bound states> here are spatially distributed <wavefunctions> with no definite classical orbit. Their <probability density> is spherically symmetric, and their <orbital angular momentum> is zero because $\ell=0$. Their radial distributions also depend on $N$ and can have nodes. A real radial wavefunction times a global stationary phase has zero <probability current>, unlike the circulating point charge in the Bohr picture.
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