= Solution
The <risk sets> at the six event times are $(7,6,5,3,2,1)$, each with one event: the censoring between $t_3$ and $t_4$ removes the seventh individual before the fourth event. Thus \b[the survivor estimate after the fifth event] is
$$
\boxed{\widehat F_5^*=\frac67\frac56\frac45\frac23\frac12=\frac4{21}.}
$$
Conditional on reaching $t_4$, the event mass at $t_4$ is $1/3$, that at $t_5$ is $(2/3)(1/2)$, and that at $t_6$ is $(2/3)(1/2)(1)$. Hence \b[the conditional event probabilities] are
$$
\boxed{(\widehat p_4^*,\widehat p_5^*,\widehat p_6^*)=(1/3,1/3,1/3).}
$$
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