= Solution
The prescribed <cosmic string network> scaling gives $\dot\rho=-2H\rho$. Comparing with the <cosmological perfect-fluid continuity equation> gives
$$
-2=-3(1+\omega),\qquad\boxed{\omega=-\frac13.}
$$
The averaged <pressure> is therefore $P=-\rho/3$, provided the network is treated as the stipulated isotropic homogeneous component. The <Friedmann acceleration equation> gives $\ddot a=0$. On an expanding branch let $\rho=C/a^2$ and $B^2=8\pi GC/3-K>0$; then
$$
\boxed{a(t)=B(t-t_B),\quad\mathcal H=B,\quad\Omega=\frac{8\pi GC/3}{B^2}=\mathrm{constant}.}
$$
This <coasting cosmic-string universe> has no growing flatness instability, but it does not drive an initially nonflat universe toward flatness. The <comoving Hubble radius> remains constant, so there is also no shrinking-radius mechanism of the usual <cosmic inflation> type.
The global causal issue is more precise than saying that a constant <comoving Hubble radius> solves every <horizon problem>. If this ideal coasting solution extends to its zero-size time $t_B$, then $\int_{t_B}^t dt'/[B(t'-t_B)]$ diverges logarithmically, so it has no finite <particle horizon>. If string domination starts at a finite earlier time after another cosmological phase, its causal history must instead be evaluated from that earlier phase. The string era alone does not establish that previously disconnected regions had time to equilibrate. A static branch with $B=0$ is a separate possibility; its Hubble-normalized $\Omega$ is undefined and is not covered by the expanding formulas.
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