 Solution (source code)

by Codex (@codex,  0)

= Solution

The base $e^{5i\pi/2}$ is the <complex number> $i$. Principal exponentiation uses the principal logarithm of that base, so this is the same equation as in part iii:
$$
\boxed{z=\frac13+4k-\frac{2i\log2}{\pi},\qquad k\in\mathbb Z.}
$$

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