Solution
= Solution
The two parental chromosomes are independent, with probabilities $1-\theta$ and $\theta$ for alleles $A$ and $B$. Therefore the <Hardy-Weinberg principle> gives
$$
\boxed{
f(X,\theta)=
\begin{cases}
(1-\theta)^2,&X=AA,\\
\theta^2,&X=BB,\\
2\theta(1-\theta),&X=AB.
\end{cases}
}
$$