= Solution
Set $A=\Phi_0R_0^\beta<0$, $q=\lambda^2$ and $s=R^2+qz^2$. The <flattened power-law gravitational potential> is $\Phi=As^{-\beta/2}$. In axisymmetric <cylindrical coordinates>, the <Poisson equation for Newtonian gravity> gives
$$
4\pi G\rho=\frac1R\partial_R(R\partial_R\Phi)+\partial_z^2\Phi.
$$
The first derivatives are $\partial_R\Phi=-\beta ARs^{-(\beta+2)/2}$ and $\partial_z\Phi=-\beta Aqzs^{-(\beta+2)/2}$. Differentiating again and collecting powers gives
$$
\nabla^2\Phi=-\beta As^{-(\beta+4)/2}\left[(2+q)s-(\beta+2)(R^2+q^2z^2)\right].
$$
Therefore the required <mass density> is
$$
\boxed{\rho(R,z)=-\frac{\beta\Phi_0R_0^\beta}{4\pi G}\frac{(\lambda^2-\beta)R^2+\lambda^2[2-(\beta+1)\lambda^2]z^2}{(R^2+\lambda^2z^2)^{(\beta+4)/2}}.}
$$
This is a formal density for arbitrary $\lambda$, but a physical <dark matter> distribution must be nonnegative. The <density positivity for a flattened power-law potential> condition is
$$
\boxed{\beta\leq\lambda^2\leq\frac2{\beta+1}.}
$$
Necessity follows by evaluating on the midplane and symmetry axis; sufficiency follows because both numerator coefficients are then nonnegative. In this range the origin is a locally integrable density cusp: the mass enclosed near radius $r$ scales as $r^{1-\beta}$ and tends to zero, so no point mass needs adding. The scale-free distribution has infinite total mass at large radius and represents an idealized background, not a finite isolated halo.
For the cold, non-self-gravitating disk, radial balance of a <circular orbit> is $R\Omega^2=\partial_R\Phi(R,0)$. Thus
$$
\boxed{\Omega^2(R)=-\beta\Phi_0R_0^\beta R^{-\beta-2},\qquad\Omega(R)=\frac{\sqrt{-\beta\Phi_0}}{R_0}\left(\frac R{R_0}\right)^{-(\beta+2)/2}.}
$$
The displayed positive root chooses the rotation orientation; the opposite orientation has the negative of this angular frequency.
Back to article page