Solution
= Solution
If $K<0$ everywhere, compactness makes the integral negative, so $\chi(S)<0$. For every triangulation, $3F=2E$ again yields the general identity
$$
\overline d=6-\frac{6\chi(S)}{V}.
$$
Since $V\geq1$ and $\chi(S)<0$,
$$
\boxed{6<\overline d\leq6-6\chi(S)}.
$$
This supplies bounds depending only on the surface.