Solution
= Solution
Let $\kappa=|N|$. If the <saturated model> $N$ had a basis $B$ of cardinality below $\kappa$, then $N=\operatorname{acl}(B)$ would omit the consistent <generic type in a strongly minimal theory> over $B$. This contradicts $\kappa$-saturation. A basis is a subset of $N$, so its cardinality is at most $\kappa$. Therefore
$$
\boxed{N\text{ saturated}\Longrightarrow\dim(N)=|N|.}
$$