Solution
= Solution
For an <oblique shock>, boost parallel to the front by the upstream tangential speed. The transformed upstream flow is normal, so part b applies. Inviscid momentum balance has no tangential stress and therefore makes the tangential velocity continuous. Transforming back gives
$$
\boxed{u_{y1}=u_{y2}},
$$
while all normal velocity, density, and pressure relations from part b remain unchanged with $M_x$ the normal Mach number.