A $Z$ measurement is a <quantum measurement in the computational basis>. To measure $X$, apply a <Hadamard gate>, measure $Z$, and apply another <Hadamard gate> to the measured qubit. Since $HXH=Z$, this gives the $X$ outcome and leaves the qubit in the corresponding $X$ <eigenstate>.

Solution

Past exam of the mathematics course of the University of Cambridge / 2022 / iii / Paper 324 / 1 / a / i / Solution

 Solution (source code)