= Solution
For $N_f=1$, antisymmetry makes the would-be baryons vanish, and the only generator of the <chiral ring of a supersymmetric gauge theory> is the <meson operator in supersymmetric quantum chromodynamics> $M=\widetilde\Phi\Phi$. It obeys no classical constraint. Holomorphy, mass dimension and all three U(1) charges uniquely permit the <Affleck–Dine–Seiberg superpotential>
$$
\boxed{W_{\rm dyn}=\frac{\Lambda^5}{M}}
$$
up to a nonzero constant absorbed into $\Lambda$. Since $\partial_MW=-\Lambda^5/M^2$ never vanishes at finite $M$, there is no finite supersymmetric ground state. Instead the potential approaches zero as $|M|\to\infty$: the theory has a supersymmetric runaway vacuum at infinity.
Back to article page