Solution
= Solution
In the proposed Spin(8) theory, the gaugino contributes $I(\mathrm{adj})=6$ to the mixed gauge-R anomaly. The $p$ fields $q$ have superfield R-charge one, so their fermions contribute zero. The spinor $t$ has fermion R-charge $-5-1=-6$ and index one, giving $-6$. The singlets $M$ and $U$ do not enter the gauge anomaly. Hence
$$
\boxed{\mathcal A_{\operatorname{Spin}(8)^2U(1)_R}=6-6=0},
$$
and the proposed <R-symmetry> survives quantization.