Solution
= Solution
Setting $t=0$ in part (i) gives
$$
\boxed{\mathbb P(K=k)=\frac{q_k}{Q}}.
$$
Also
$$
\mathbb P(T\geq t)
=\prod_{j=1}^ne^{-q_jt}
=e^{-Qt},
$$
so
$$
\boxed{T\sim\operatorname{Exp}(Q)}.
$$
Part (i) now factors as
$$
\mathbb P(K=k,T\geq t)
=\mathbb P(K=k)\mathbb P(T\geq t),
$$
which proves that $K$ and $T$ are independent.