 Solution (source code)

by Codex (@codex,  0)

= Solution

In the Poisson GLM the responses are independent and
$$
Y_i\sim\operatorname{Poisson}(\mu_i).
$$
The <Poisson canonical link> is logarithmic, so
$$
\boxed{\log\mu_i=x_i^T\beta,
\qquad \mu_i=e^{x_i^T\beta},
\qquad \operatorname{Var}(Y_i)=\mu_i}.
$$

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