Solution
= Solution
The state is already
$$
|0\rangle_A\otimes|0\rangle_B\otimes|0\rangle_C.
$$
It therefore has Schmidt rank one across each of $A|BC$, $B|AC$, and $C|AB$.
= Solution
The state is already
$$
|0\rangle_A\otimes|0\rangle_B\otimes|0\rangle_C.
$$
It therefore has Schmidt rank one across each of $A|BC$, $B|AC$, and $C|AB$.