Solution
= Solution
Alice performs the operation and measurement from part (iii) and sends the one-bit outcome to Bob. If the bit is $0$, Bob does nothing. If it is $1$, Bob applies $ZX$, which maps $|\psi_2\rangle$ to $|\psi_1\rangle$ by part (i). In either case Bob finishes with the known target state $|\psi_1\rangle$, using one shared Bell pair and one classical bit.