Moving from $A_1$ to $A_n$, the colour changes an odd number of times because the endpoints have opposite colours: every change toggles the current colour, while every nonchange preserves it. Formally, encode red and green by zero and one; the sum modulo two of adjacent differences is the endpoint difference, which is one.


Solution

Past exam of the mathematics course of the University of Cambridge / 2024 / ii / Paper 4 / 12G / a / Solution

 Solution (source code)